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發佈時間:2019-11-07 (更新:2019-11-07 23:36) | 發佈者:hurt |
標題:108-1 二上數學 2-2 根式的運算練習題 | |
一、選擇:
1. 算式 \((-\sqrt{\frac{8}{15}})\div \sqrt{\frac{6}{5}}\times (-\sqrt{\frac{3}{2}})\) 的值為何?
(A) \(-\frac{2\sqrt{6}}{5}\)
(B) \(-\frac{\sqrt{6}}{3}\)
(C) \(\frac{2\sqrt{6}}{5}\)
(D) \(\frac{\sqrt{6}}{3}\)
答案:D
2. 化簡 \(\sqrt{\frac{5}{6}}\div \sqrt{1\frac{1}{24}}\div (-\sqrt{\frac{3}{5}})\) 之後,可得下列哪一個結果?
(A) \(-\frac{2\sqrt{3}}{3}\)
(B) \(\frac{2\sqrt{3}}{3}\)
(C) \(-\frac{2}{3}\)
(D) \(\frac{2}{3}\)
答案:A
3. 計算 \(\sqrt{0.25}-\sqrt{\frac{9}{4}}-\sqrt{(-9)^{2}} =\)
(A) \(10\)
(B) \(8\)
(C) \(-10\)
(D) \(-8\)
答案:C
4. 若 \(\sqrt{121}+\sqrt{169} = 2\sqrt{x}\) 則 \(x =\)
(A) \(144\)
(B) \(145\)
(C) \(225\)
(D) \(290\)
答案:A
5. 計算 \(\sqrt{30}\div (-\sqrt{2})\div (-\sqrt{3}) =\)
(A) \(\sqrt{5}\)
(B) \(\sqrt{6}\)
(C) \(-\sqrt{5}\)
(D) \(-\sqrt{6}\)
答案:A
二、填充:
1. 計算並化簡 \(\sqrt{8}+\sqrt{24}-\sqrt{6}-\sqrt{18} = ----\)
答案: \(\sqrt{6}-\sqrt{2}\)
2. 計算 \(\frac{\sqrt{3}}{\sqrt{5}}\times \frac{\sqrt{6}}{\sqrt{15}}\div \frac{\sqrt{3}}{\sqrt{10}}\div \frac{\sqrt{2}}{\sqrt{5}}\) \(= ----\)
答案:\(\sqrt{2}\)
3. 計算並化簡下列各式:
(1) \(\sqrt{8}-\sqrt{12}+\sqrt{18}+\sqrt{27} = ----\)
(2) \(\sqrt{6}-\sqrt{\frac{3}{2}}-\sqrt{\frac{2}{3}} =\)
答案:
(1) \(5\sqrt{2}+\sqrt{3}\)
(2) \(\frac{\sqrt{6}}{6}\)
4. 運用乘法公式化簡下列各方根的運算。
(1) \((\sqrt{5}+\sqrt{3})^{2} = ----\)
(2) \((\sqrt{5}-\sqrt{7})(\sqrt{7}+\sqrt{5}) = ----\) .
答案:
(1) \(6+2\sqrt{15}\)
(2) \(-2\)
5. 計算下列各式,並將結果化成最簡根式。
(1) \((5\sqrt{2}+2\sqrt{3})^{2}= ----\)
(2) \((5\sqrt{2}-2\sqrt{3})^{2}= ----\) .
(3) \((5\sqrt{2}+2\sqrt{3})(5\sqrt{2}-2\sqrt{3}) = ----\)
答案:
(1) \(62+20\sqrt{6}\)
(2) \(62-20\sqrt{3}\)
(3) \(38\)
● 108-1_二上數學_2-2_根式的運算練習題.txt ● 108-1_二上數學_2-2_根式的運算練習題(含答).rtf |